![]() ∫ a b f(t) dt - F(b) = ∫ a a f(t) dt - F(a)īy a property of definite integrals, ∫ a a f(t) dt = 0. Thus, h(x) is a constant function over and hence We know that h(x) is continuous on (as both g(x) and F(x) are continuous on the same interval) and from the above equation h'(x) = 0. Let us define another function h(x) such that Then by the first part of the fundamental theorem of calculus (FTC 1), g'(x) = f(x). Let us define a new function g(x) such that ![]() It is given that F(x) is an anti derivative of f(x).
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |